| Author |
Message |
Marco Jongen
Rating: N/A
Votes: 0 (Vote!) | | Posted on Friday, May 03, 2002 - 06:59 am: | 
|
Does anyone have a good solution for removing leading zero's?
I have tried the pub.remove service, but this creates the following, with these values:
inString:
searchString:
replaceString:
useRegex:
inString is +0000123979708900
Result is +123979789
And it is supposed to be +123979708900
Hope anyone can help with this... |
Rob Eamon
Rating: N/A
Votes: 0 (Vote!) | | Posted on Friday, May 03, 2002 - 11:16 am: |
|
Here's Java code that you can adapt to put into a Java service:
// Remove leading characters from a string.
//
// @return java.lang.String String with all leading characters specified by paramter 'c' removed
// @param s java.lang.String Source string
// @param c char Leading characters to remove
String trimLeft(String s, char c)
{
if(s == null)
return "";
int len = s.length();
int n = 0;
while(n < len && s.charAt(n) == c)
++n;
return s.substring(n);
}
If your string starts with a sign, you'll need to remove it before calling this service and then put it back after you get the trimmed string. |
Michael Herzog
Rating: N/A
Votes: 0 (Vote!) | | Posted on Friday, May 03, 2002 - 11:30 am: |
|
If you can remove the sign, you can also just wack this string into an integer:
String s_no_sign = "0000123979708900";
Long n = new Long(s_no_sign); |
Rob Eamon
Rating: N/A
Votes: 0 (Vote!) | | Posted on Friday, May 03, 2002 - 11:37 am: |
|
My previous post with the Java code for trimming leading characters didn't get formatted correctly in the e-mail. Please visit the discussion board to see the full post. |
Rob Eamon
Rating: N/A
Votes: 0 (Vote!) | | Posted on Friday, May 03, 2002 - 12:11 pm: |
|
Here's a way to do it without needing to strip the leading sign:
java.text.DecimalFormat df = new java.text.DecimalFormat();
df.setPositivePrefix("+");
Number n = df.parse("+000012397908900");
return n.toString(); |
Erik Versteijnen
Rating: N/A
Votes: 0 (Vote!) | | Posted on Friday, May 03, 2002 - 03:53 pm: |
|
Just use 'pub.string:replace':
inString: +0000123979708900
searchString: ^\+0+
replaceString: +
useRegex: true |
Rob Eamon
Rating: N/A
Votes: 0 (Vote!) | | Posted on Friday, May 03, 2002 - 04:31 pm: |
|
I always forget about using regular expressions! Awsome solution! |
viv (Unregistered Guest)
Unregistered guest Rating: N/A
Votes: 0 (Vote!) | | Posted on Thursday, September 29, 2005 - 02:22 am: |
|
I tried the reg exp to remove just the trailing zeros and failed, can you suggest how to remove just the trailing '0's |
Puneet Verma
Intermediate Member Username: puneetverma Post Number: 48
Registered: 12-2003 Rating: N/A
Votes: 0 (Vote!) | | Posted on Thursday, September 29, 2005 - 04:06 am: |
|
Viv,
You need to use the $ after the expression to remove the trailing zeroes.
inString: 12345000
searchString: 0+$
replaceString:
useRegex: true
HTH..
Thanks,
Puneet Verma |
